概率论 (Summer 2013)/Problem Set 3: Difference between revisions

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== Problem 4 ==
== Problem 4 ==
(Due to D.R. Karger and R. Motwani.)
An <math>(n,m)</math>-safe set instance consists of a universe <math>U</math> of size <math>n</math>, a safe set <math>S\subseteq U</math>, and <math>m</math> target sets <math>T_1,\dots,T_m\subseteq U</math> such that
* <math>|S|=|T_1|=\cdots=|T_m|</math>,
* and, for <math>1\le i\le m, S\cap T_i=\emptyset</math>.
An <i>isolator</i> for a safe set instance is a set <math>I\subseteq U</math> that intersects all the target sets but not the safe set. An <i><math>(n,m)</math>-universal isolating family <math>\mathcal{F}</math></i> is a collection of subsets of <math>U</math> such that <math>\mathcal{F}</math> contains an isolator for any <math>(n,m)</math>-safe set instance. Show that there exists a <math>(n,m)</math>-universal isolating family <math>\mathcal{F}</math> such that <math>|\mathcal{F}|</math> is polynomially bounded in <math>n</math> and <math>m</math>.


== Problem 5 ==
== Problem 5 ==

Revision as of 17:19, 18 July 2013

Problem 1

A set of vertices [math]\displaystyle{ D\subseteq V }[/math] of graph [math]\displaystyle{ G(V,E) }[/math] is a dominating set if for every [math]\displaystyle{ v\in V }[/math], either [math]\displaystyle{ v\in D }[/math] or one of its neighbour is in [math]\displaystyle{ D }[/math]. The problem of computing minimum dominating set is NP-hard.

  • Prove that for every [math]\displaystyle{ d }[/math]-regular graph with [math]\displaystyle{ n }[/math] vertices, there exists a dominating set with size at most [math]\displaystyle{ \frac{n(1+\ln(d+1))}{d+1} }[/math].
  • Try to obtain an upper bound for the size of dominating set using Lovász Local Lemma. Is it better or worse than previous one? Why?

Problem 2

Let [math]\displaystyle{ H(W,F) }[/math] be a graph and [math]\displaystyle{ n\gt |W| }[/math] be an integer. It is known that for some graph [math]\displaystyle{ G(V,E) }[/math] such that [math]\displaystyle{ |V|=n }[/math], [math]\displaystyle{ |E|=m }[/math], [math]\displaystyle{ G }[/math] does not contain [math]\displaystyle{ H }[/math] as a subgraph. Prove that for [math]\displaystyle{ k\gt \frac{n^2\ln n}{m} }[/math], there is an edge [math]\displaystyle{ k }[/math]-coloring for [math]\displaystyle{ K_n }[/math] that [math]\displaystyle{ K_n }[/math] contains no monochromatic [math]\displaystyle{ H }[/math].

Remark: Let [math]\displaystyle{ E=\binom{V}{2} }[/math] be the edge set of [math]\displaystyle{ K_n }[/math]. "An edge [math]\displaystyle{ k }[/math]-coloring for [math]\displaystyle{ K_n }[/math]" is a mapping [math]\displaystyle{ f:E\to[k] }[/math].

Problem 3

Let [math]\displaystyle{ G(V,E) }[/math] be a cycle of length [math]\displaystyle{ 4n }[/math] and let [math]\displaystyle{ V=V_1\cup V_2\cup\dots V_n }[/math] be a partition of its [math]\displaystyle{ 4n }[/math] vertices into [math]\displaystyle{ n }[/math] pairwise disjoint subsets, each of cardinality 4. Is it true that there must be an independent set of [math]\displaystyle{ G }[/math] containing precisely one vertex from each [math]\displaystyle{ V_i }[/math]? (Prove or supply a counter example.)

Hint: you can use Lovász Local Lemma.

Problem 4

(Due to D.R. Karger and R. Motwani.)

An [math]\displaystyle{ (n,m) }[/math]-safe set instance consists of a universe [math]\displaystyle{ U }[/math] of size [math]\displaystyle{ n }[/math], a safe set [math]\displaystyle{ S\subseteq U }[/math], and [math]\displaystyle{ m }[/math] target sets [math]\displaystyle{ T_1,\dots,T_m\subseteq U }[/math] such that

  • [math]\displaystyle{ |S|=|T_1|=\cdots=|T_m| }[/math],
  • and, for [math]\displaystyle{ 1\le i\le m, S\cap T_i=\emptyset }[/math].

An isolator for a safe set instance is a set [math]\displaystyle{ I\subseteq U }[/math] that intersects all the target sets but not the safe set. An [math]\displaystyle{ (n,m) }[/math]-universal isolating family [math]\displaystyle{ \mathcal{F} }[/math] is a collection of subsets of [math]\displaystyle{ U }[/math] such that [math]\displaystyle{ \mathcal{F} }[/math] contains an isolator for any [math]\displaystyle{ (n,m) }[/math]-safe set instance. Show that there exists a [math]\displaystyle{ (n,m) }[/math]-universal isolating family [math]\displaystyle{ \mathcal{F} }[/math] such that [math]\displaystyle{ |\mathcal{F}| }[/math] is polynomially bounded in [math]\displaystyle{ n }[/math] and [math]\displaystyle{ m }[/math].

Problem 5