计算复杂性 (Fall 2019)/作业5已提交名单 and 高级算法 (Fall 2019)/Problem Set 3: Difference between pages

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*作业电子版于2019/11/26 23:59 之前提交到邮箱 <font color=blue>njuadvalg@163.com</font>
*每道题目的解答都要有<font color="red" size=5>完整的解题过程</font>。中英文不限。


{| class="wikitable"
== Problem 1==
| 161140077 || 张昕渊
Let <math>G(V,E)</math> be an undirected graph with positive edge weights <math>w:E\to\mathbb{Z}^+</math>. Given a partition of <math>V</math> into <math>k</math> disjoint subsets <math>S_1,S_2,\ldots,S_k</math>, we define
|-
:<math>w(S_1,S_2,\ldots,S_k)=\sum_{uv\in E\atop \exists i\neq j: u\in S_i,v\in S_j}w(uv)</math>
| DZ1833022 || 王国华
as the cost of the '''<math>k</math>-cut''' <math>\{S_1,S_2,\ldots,S_k\}</math>. Our goal is to find a <math>k</math>-cut with maximum cost.
|-
# Give a poly-time greedy algorithm for finding the weighted max <math>k</math>-cut. Prove that the approximation ratio is <math>(1-1/k)</math>.
| 171860558 || 董杨静
# Consider the following local search algorithm for the weighted max cut (max 2-cut).
|-
::Fill in the blank parenthesis. Give an analysis of the running time of the algorithm. And prove that the approximation ratio is 0.5.
| MG1933029 || 蒋松儒
start with an arbitrary bipartition of <math>V</math> into disjoint <math>S_0,S_1</math>;
|-
while (true) do
| mf1933074 || 乔裕哲
    if <math>\exists i\in\{0,1\}</math> and <math>v\in S_i</math> such that <font color=red>(______________)</font>
|}
      then <math>v</math> leaves <math>S_i</math> and joins <math>S_{1-i}</math>;
      continue;
    end if
    break;
end
 
== Problem 2==
Given <math>m</math> subsets <math>S_1,S_2,\ldots, S_m\subseteq U</math> of a universe <math>U</math> of size <math>n</math>, we want to find a <math>C\subseteq\{1,2,\ldots, {m}\}</math> of fixed size <math>k=|C|</math> with the maximum '''coverage''' <math>\left|\bigcup_{i\in C}S_i\right|</math>.
 
* Give a poly-time greedy algorithm for the problem. Prove that the approximation ratio is <math>1-(1-1/k)^k>1-1/e</math>.
 
 
== Problem 3==
In the ''maximum directed cut'' (MAX-DICUT) problem, we are given as input a directed graph <math>G(V,E)</math>. The goal is to partition <math>V</math> into disjoint <math>S</math> and <math>T</math> so that the number of edges in <math>E(S,T)=\{(u,v)\in E\mid u\in S, v\in T\}</math> is maximized. The following is the integer program for MAX-DICUT:
:::<math>
\begin{align}
\text{maximize} &&& \sum_{(u,v)\in E}y_{u,v}\\
\text{subject to} && y_{u,v} &\le x_u, & \forall (u,v)&\in E,\\
&& y_{u,v} &\le 1-x_v, & \forall (u,v)&\in E,\\
&& x_v &\in\{0,1\}, & \forall v&\in V,\\
&&  y_{u,v} &\in\{0,1\}, & \forall (u,v)&\in E.
\end{align}
</math>
Let <math>x_v^*,y_{u,v}^*</math> denote the optimal solution to the '''LP-relaxation''' of the above integer program.
* Apply the randomized rounding such that for every <math>v\in V</math>, <math>\hat{x}_v=1</math> independently with probability <math>x_v^*</math>. Analyze the approximation ratio (between the expected size of the random cut and OPT).
* Apply another randomized rounding such that for every <math>v\in V</math>, <math>\hat{x}_v=1</math> independently with probability <math>1/4+x_v^*/2</math>. Analyze the approximation ratio for this algorithm.
 
== Problem 4==
Recall the MAX-SAT problem and its integer program:
:::<math>
\begin{align}
\text{maximize} &&& \sum_{j=1}^my_j\\
\text{subject to} &&& \sum_{i\in S_j^+}x_i+\sum_{i\in S_j^-}(1-x_i)\ge y_j, && 1\le j\le m,\\
&&& x_i\in\{0,1\}, && 1\le i\le n,\\
&&& y_j\in\{0,1\}, && 1\le j\le m.
\end{align}
</math>
Recall that <math>S_j^+,S_j^-\subseteq\{1,2,\ldots,n\}</math> are the respective sets of variables appearing positively and negatively in clause <math>j</math>.
 
Let <math>x_i^*,y_j^*</math> denote the optimal solution to the '''LP-relaxation''' of the above integer program. In our class we learnt that if <math>\hat{x}_i</math> is round to 1 independently with probability <math>x_i^*</math>, we have approximation ratio <math>1-1/\mathrm{e}</math>.
 
We consider a generalized rounding scheme such that every <math>\hat{x}_i</math> is round to 1 independently with probability <math>f(x_i^*)</math> for some function <math>f:[0,1]\to[0,1]</math> to be specified.
* Suppose <math>f(x)</math> is an arbitrary function satisfying that <math>1-4^{-x}\le f(x)\le 4^{x-1}</math> for any <math>x\in[0,1]</math>. Show that with this rounding scheme, the approximation ratio (between the expected number of satisfied clauses and OPT) is at least <math>3/4</math>.
* Derandomize this algorithm through conditional expectation and give a deterministic polynomial time algorithm with approximation ratio <math>3/4</math>.
* Is it possible that for some more clever <math>f</math> we can do better than this? Try to justify your argument.
 
==Problem 5 ==
The following is the weighted version of set cover problem:
 
Given <math>m</math> subsets <math>S_1,S_2,\ldots,S_m\subseteq U</math>, where <math>U</math> is a universe of size <math>n=|U|</math>, and each subset <math>S_i</math> is assigned a positive weight <math>w_i>0</math>, the goal is to find a <math>C\subseteq\{1,2,\ldots,m\}</math> such that <math>U=\bigcup_{i\in C}S_i</math> and the total weight <math>\sum_{I\in C}w_i</math> is minimized.
* Give an integer program for the problem and its LP relaxation.
* Consider the following idea of randomized rounding: independently round each fractional value to <math>\{0,1\}</math> with the probability of the fractional value itself; and repeatedly apply this process to the variables rounded to 0 in previous iterations until <math>U</math> is fully covered. Show that this can return a set cover with <math>O(\log n)</math> approximation ratio with probability at least <math>0.99</math>.

Latest revision as of 09:33, 12 November 2019

  • 作业电子版于2019/11/26 23:59 之前提交到邮箱 njuadvalg@163.com
  • 每道题目的解答都要有完整的解题过程。中英文不限。

Problem 1

Let [math]\displaystyle{ G(V,E) }[/math] be an undirected graph with positive edge weights [math]\displaystyle{ w:E\to\mathbb{Z}^+ }[/math]. Given a partition of [math]\displaystyle{ V }[/math] into [math]\displaystyle{ k }[/math] disjoint subsets [math]\displaystyle{ S_1,S_2,\ldots,S_k }[/math], we define

[math]\displaystyle{ w(S_1,S_2,\ldots,S_k)=\sum_{uv\in E\atop \exists i\neq j: u\in S_i,v\in S_j}w(uv) }[/math]

as the cost of the [math]\displaystyle{ k }[/math]-cut [math]\displaystyle{ \{S_1,S_2,\ldots,S_k\} }[/math]. Our goal is to find a [math]\displaystyle{ k }[/math]-cut with maximum cost.

  1. Give a poly-time greedy algorithm for finding the weighted max [math]\displaystyle{ k }[/math]-cut. Prove that the approximation ratio is [math]\displaystyle{ (1-1/k) }[/math].
  2. Consider the following local search algorithm for the weighted max cut (max 2-cut).
Fill in the blank parenthesis. Give an analysis of the running time of the algorithm. And prove that the approximation ratio is 0.5.
start with an arbitrary bipartition of [math]\displaystyle{ V }[/math] into disjoint [math]\displaystyle{ S_0,S_1 }[/math];
while (true) do
   if [math]\displaystyle{ \exists i\in\{0,1\} }[/math] and [math]\displaystyle{ v\in S_i }[/math] such that (______________)
      then [math]\displaystyle{ v }[/math] leaves [math]\displaystyle{ S_i }[/math] and joins [math]\displaystyle{ S_{1-i} }[/math];
      continue;
   end if
   break;
end

Problem 2

Given [math]\displaystyle{ m }[/math] subsets [math]\displaystyle{ S_1,S_2,\ldots, S_m\subseteq U }[/math] of a universe [math]\displaystyle{ U }[/math] of size [math]\displaystyle{ n }[/math], we want to find a [math]\displaystyle{ C\subseteq\{1,2,\ldots, {m}\} }[/math] of fixed size [math]\displaystyle{ k=|C| }[/math] with the maximum coverage [math]\displaystyle{ \left|\bigcup_{i\in C}S_i\right| }[/math].

  • Give a poly-time greedy algorithm for the problem. Prove that the approximation ratio is [math]\displaystyle{ 1-(1-1/k)^k\gt 1-1/e }[/math].


Problem 3

In the maximum directed cut (MAX-DICUT) problem, we are given as input a directed graph [math]\displaystyle{ G(V,E) }[/math]. The goal is to partition [math]\displaystyle{ V }[/math] into disjoint [math]\displaystyle{ S }[/math] and [math]\displaystyle{ T }[/math] so that the number of edges in [math]\displaystyle{ E(S,T)=\{(u,v)\in E\mid u\in S, v\in T\} }[/math] is maximized. The following is the integer program for MAX-DICUT:

[math]\displaystyle{ \begin{align} \text{maximize} &&& \sum_{(u,v)\in E}y_{u,v}\\ \text{subject to} && y_{u,v} &\le x_u, & \forall (u,v)&\in E,\\ && y_{u,v} &\le 1-x_v, & \forall (u,v)&\in E,\\ && x_v &\in\{0,1\}, & \forall v&\in V,\\ && y_{u,v} &\in\{0,1\}, & \forall (u,v)&\in E. \end{align} }[/math]

Let [math]\displaystyle{ x_v^*,y_{u,v}^* }[/math] denote the optimal solution to the LP-relaxation of the above integer program.

  • Apply the randomized rounding such that for every [math]\displaystyle{ v\in V }[/math], [math]\displaystyle{ \hat{x}_v=1 }[/math] independently with probability [math]\displaystyle{ x_v^* }[/math]. Analyze the approximation ratio (between the expected size of the random cut and OPT).
  • Apply another randomized rounding such that for every [math]\displaystyle{ v\in V }[/math], [math]\displaystyle{ \hat{x}_v=1 }[/math] independently with probability [math]\displaystyle{ 1/4+x_v^*/2 }[/math]. Analyze the approximation ratio for this algorithm.

Problem 4

Recall the MAX-SAT problem and its integer program:

[math]\displaystyle{ \begin{align} \text{maximize} &&& \sum_{j=1}^my_j\\ \text{subject to} &&& \sum_{i\in S_j^+}x_i+\sum_{i\in S_j^-}(1-x_i)\ge y_j, && 1\le j\le m,\\ &&& x_i\in\{0,1\}, && 1\le i\le n,\\ &&& y_j\in\{0,1\}, && 1\le j\le m. \end{align} }[/math]

Recall that [math]\displaystyle{ S_j^+,S_j^-\subseteq\{1,2,\ldots,n\} }[/math] are the respective sets of variables appearing positively and negatively in clause [math]\displaystyle{ j }[/math].

Let [math]\displaystyle{ x_i^*,y_j^* }[/math] denote the optimal solution to the LP-relaxation of the above integer program. In our class we learnt that if [math]\displaystyle{ \hat{x}_i }[/math] is round to 1 independently with probability [math]\displaystyle{ x_i^* }[/math], we have approximation ratio [math]\displaystyle{ 1-1/\mathrm{e} }[/math].

We consider a generalized rounding scheme such that every [math]\displaystyle{ \hat{x}_i }[/math] is round to 1 independently with probability [math]\displaystyle{ f(x_i^*) }[/math] for some function [math]\displaystyle{ f:[0,1]\to[0,1] }[/math] to be specified.

  • Suppose [math]\displaystyle{ f(x) }[/math] is an arbitrary function satisfying that [math]\displaystyle{ 1-4^{-x}\le f(x)\le 4^{x-1} }[/math] for any [math]\displaystyle{ x\in[0,1] }[/math]. Show that with this rounding scheme, the approximation ratio (between the expected number of satisfied clauses and OPT) is at least [math]\displaystyle{ 3/4 }[/math].
  • Derandomize this algorithm through conditional expectation and give a deterministic polynomial time algorithm with approximation ratio [math]\displaystyle{ 3/4 }[/math].
  • Is it possible that for some more clever [math]\displaystyle{ f }[/math] we can do better than this? Try to justify your argument.

Problem 5

The following is the weighted version of set cover problem:

Given [math]\displaystyle{ m }[/math] subsets [math]\displaystyle{ S_1,S_2,\ldots,S_m\subseteq U }[/math], where [math]\displaystyle{ U }[/math] is a universe of size [math]\displaystyle{ n=|U| }[/math], and each subset [math]\displaystyle{ S_i }[/math] is assigned a positive weight [math]\displaystyle{ w_i\gt 0 }[/math], the goal is to find a [math]\displaystyle{ C\subseteq\{1,2,\ldots,m\} }[/math] such that [math]\displaystyle{ U=\bigcup_{i\in C}S_i }[/math] and the total weight [math]\displaystyle{ \sum_{I\in C}w_i }[/math] is minimized.

  • Give an integer program for the problem and its LP relaxation.
  • Consider the following idea of randomized rounding: independently round each fractional value to [math]\displaystyle{ \{0,1\} }[/math] with the probability of the fractional value itself; and repeatedly apply this process to the variables rounded to 0 in previous iterations until [math]\displaystyle{ U }[/math] is fully covered. Show that this can return a set cover with [math]\displaystyle{ O(\log n) }[/math] approximation ratio with probability at least [math]\displaystyle{ 0.99 }[/math].