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	<updated>2026-05-01T08:42:48Z</updated>
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	<entry>
		<id>https://tcs.nju.edu.cn/wiki/index.php?title=Chain_rule&amp;diff=7838</id>
		<title>Chain rule</title>
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		<updated>2016-07-22T04:58:35Z</updated>

		<summary type="html">&lt;p&gt;172.90.64.25: &lt;/p&gt;
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&lt;div&gt;{{Multiple issues|wikify=October 2012}}&lt;br /&gt;
The &#039;&#039;&#039;chain rule&#039;&#039;&#039; is a way of finding the derivative of a function. It is used where the function is in another function. This is called a composite function.  &lt;br /&gt;
&lt;br /&gt;
If F(x) equals two functions that we can take a derivative of, such as:&lt;br /&gt;
:&amp;lt;math&amp;gt;F(x)=f(g(x))&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
then the derivative, F prime, is&lt;br /&gt;
:&amp;lt;math&amp;gt;F&#039;(x)=f&#039;(g(x))g&#039;(x)&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
==Steps==&lt;br /&gt;
&#039;&#039;&#039;1.&#039;&#039;&#039; Find the derivative of the outside function (all of it at once).&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;2.&#039;&#039;&#039; Find the derivative of the inside function (the bit between the brackets).&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;3.&#039;&#039;&#039; Multiply the answer from the first step by the answer from the second step. This is basically the last step in solving for the derivative of a function.&lt;br /&gt;
&lt;br /&gt;
;Example;&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;F(x)=(x^2+5)^3&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;F(x)=3(x^2+5)^2&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;F&#039;(x)=3(x^2+5)^2(2x)&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;F&#039;(x)=6x(x^2+5)^2&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
In this example, the cubed sign (&amp;lt;sup&amp;gt;3&amp;lt;/sup&amp;gt;) is the outside function and &amp;lt;math&amp;gt;x^2+5&amp;lt;/math&amp;gt; is the inside function. The derivative of the outside function would be &amp;lt;math&amp;gt;3x^2&amp;lt;/math&amp;gt;, where the inside function is plugged in for x. The derivative of the inside function would be 2x, which is multiplied by &amp;lt;math&amp;gt;3(x^2+5)^2&amp;lt;/math&amp;gt; to get &amp;lt;math&amp;gt;6x(x^2+5)^2&amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
{{stub}}&lt;br /&gt;
&lt;br /&gt;
[[Category:Mathematics]]&lt;/div&gt;</summary>
		<author><name>172.90.64.25</name></author>
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