概率论与数理统计 (Spring 2023)/Problem Set 4: Difference between revisions
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*每道题目的解答都要有完整的解题过程,中英文不限。 | *每道题目的解答都要有完整的解题过程,中英文不限。 | ||
*我们推荐大家使用LaTeX, markdown等对作业进行排版。 | *我们推荐大家使用LaTeX, markdown等对作业进行排版。 | ||
*Bonus problem为附加题(选做)。 | |||
== Assumption throughout Problem Set 4== | == Assumption throughout Problem Set 4== | ||
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</li> | </li> | ||
<li> | <li> | ||
[<strong>Random semicircle</strong>] We sample <math>n</math> points within a circle <math>C=\{(x,y) \in \mathbb{R}^2 \mid x^2+y^2 \le 1\}</math> independently and uniformly at random (i.e., the density function <math>f(x,y) \propto 1_{(x,y) \in C}</math>). Find out the probability that they all lie within some semicircle | [<strong>Random semicircle</strong>] We sample <math>n</math> points within a circle <math>C=\{(x,y) \in \mathbb{R}^2 \mid x^2+y^2 \le 1\}</math> independently and uniformly at random (i.e., the density function <math>f(x,y) \propto 1_{(x,y) \in C}</math>). Find out the probability that they all lie within some semicircle of the original circle <math>C</math>. (Hint: you may apply the technique of change of variables, see [https://en.wikipedia.org/wiki/Random_variable#Functions_of_random_variables function of random variables] or Chapter 4.7 in [GS]) | ||
</li> | </li> | ||
<li> | <li> | ||
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</ul> | </ul> | ||
== Problem 2 (Modes of Convergence)== | == Problem 2 (Modes of Convergence, 15 points) (<strong>Bonus problem</strong>)== | ||
<ul> | <ul> | ||
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<li> | <li> | ||
[<strong>Extension of Borel-Cantelli Lemma</strong>] | [<strong>Extension of Borel-Cantelli Lemma</strong>] | ||
Let <math>(A_n)_{n \ge 1}</math> be events. Suppose <math>\sum_{n \ge 1} \mathbf{Pr}(A_n)=+\infty</math>. Show that | Let <math>(A_n)_{n \ge 1}</math> be events. Suppose <math>\sum_{n \ge 1} \mathbf{Pr}(A_n)=+\infty</math>. Show that | ||
<math>\mathbf{Pr}(A_n \text{ i.o.}) \ge \limsup_{n \to \infty} \frac{ \left(\sum_{k=1}^n\mathbf{Pr}(A_k)\right)^2 }{\sum_{1\le j,k \le n} \mathbf{Pr}(A_j \cap A_k)}</math>. | <math>\mathbf{Pr}(A_n \text{ i.o.}) \ge \limsup_{n \to \infty} \frac{ \left(\sum_{k=1}^n\mathbf{Pr}(A_k)\right)^2 }{\sum_{1\le j,k \le n} \mathbf{Pr}(A_j \cap A_k)}</math>. | ||
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</ul> | </ul> | ||
== Problem | == Problem 3 (LLN and CLT, 15 points + 5 points) == | ||
<strong>In this problem, you may apply the results of Laws of Large Numbers (LLN) and the Central Limit Theorem (CLT) to solve the problems.</strong> | |||
<ul> | <ul> | ||
<li>[<strong> | <li>[<strong>St. Petersburg paradox</strong>] Consider the well-known game involving a fair coin. In this game, if it takes <math>k</math> tosses to obtain a head, you will win <math>2^k</math> dollars as the reward. Despite the game's expected reward being infinite, people tend to offer relatively modest amounts to participate. The following provides a mathematical explanation for this phenomenon. | ||
<ul> | <ul> | ||
<li> | <li> | ||
For each <math>n \ge 1</math>, let <math>X_{n,1}, X_{n,2},\ldots, X_{n,k}</math> be independent random variables. Furthermore, let <math>b_n > 0</math> be real numbers with <math>b_n \to \infty</math> and <math>\widetilde{X}_{n,k} = X_{n,k} \mathbf{1}_{|X_{n,k}| \le b_n}</math> for all <math>1 \le k \le n</math>. If <math>\sum_{k=1}^n \mathbf{Pr}(|X_{n,k}| > b_n) \to 0</math> and <math>b_n^{-2} \sum_{k=1}^n \mathbf{E}[\widetilde{X}_{n,k}^2] \to 0</math> when <math>n \to \infty</math>, then <math>(S_n-a_n)/b_n \overset{P}{\to} 0 </math>, where <math>S_n = \sum_{k=1}^n | For each <math>n \ge 1</math>, let <math>X_{n,1}, X_{n,2},\ldots, X_{n,k}</math> be independent random variables. Furthermore, let <math>b_n > 0</math> be real numbers with <math>b_n \to \infty</math> and <math>\widetilde{X}_{n,k} = X_{n,k} \mathbf{1}_{|X_{n,k}| \le b_n}</math> for all <math>1 \le k \le n</math>. If <math>\sum_{k=1}^n \mathbf{Pr}(|X_{n,k}| > b_n) \to 0</math> and <math>b_n^{-2} \sum_{k=1}^n \mathbf{E}[\widetilde{X}_{n,k}^2] \to 0</math> when <math>n \to \infty</math>, then <math>(S_n-a_n)/b_n \overset{P}{\to} 0 </math>, where <math>S_n = \sum_{k=1}^n X_{n,k}</math> and <math>a_n = \sum_{k=1}^n \mathbf{E}[\widetilde{X}_{n,k}]</math>. | ||
</li> | </li> | ||
<li> | <li> | ||
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</li> | </li> | ||
<li> | <li> (<strong>Bonus problem, 5 points</strong>) | ||
Let <math>S_n</math> be the total winnings after playing <math>n</math> rounds of the game. Prove that <math> \limsup_{n \to \infty} \frac{S_n}{n \log_2 n} = \infty</math> almost surely. (Hint: You may use Borel-Cantelli lemmas) | Let <math>S_n</math> be the total winnings after playing <math>n</math> rounds of the game. Prove that <math> \limsup_{n \to \infty} \frac{S_n}{n \log_2 n} = \infty</math> almost surely. (Hint: You may use Borel-Cantelli lemmas) | ||
</li> | </li> | ||
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<li> | <li> | ||
[<strong>Asymptotic equipartition property</strong>] Let <math>X_1,X_2,\ldots \in \{1,2,\ldots,r\}</math> be independent random variables with density function <math>p</math>. Let <math>\pi_n(\omega) = | [<strong>Asymptotic equipartition property</strong>] Let <math>X_1,X_2,\ldots \in \{1,2,\ldots,r\}</math> be independent random variables with density function <math>p</math>. Let <math>\pi_n(\omega) = \prod_{i=1}^n p(X_i(\omega))</math> be the probability of the realization we observed in the first <math>n</math> random variables. Let <math>H = -\sum_{k=1}^r p(k) \log p(k)</math> be the entropy of <math>X_1</math>. Prove that for any <math>\epsilon >0 </math>, <math>\mathbf{Pr}\left(e^{-n(H+\epsilon)} < \pi_n(\omega) < e^{-n(H-\epsilon)}\right) \to 1</math> when <math>n \to \infty</math>. | ||
</li> | </li> | ||
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</ul> | </ul> | ||
== Problem | == Problem 4 (Concentration of measure) == | ||
<ul> | <ul> | ||
<li> | <li> | ||
[<strong> | [<strong>Tossing coins</strong>] We repeatedly toss a fair coin (with an equal probability of heads and tails). Let the random variable <math>X</math> be the number of throws required to obtain a total of <math>n</math> heads. Show that <math>\textbf{Pr}[X > 2n + 2\sqrt{n\log n}]\leq O(1/n)</math>. | ||
</li> | </li> | ||
<li> | <li> | ||
[<strong> | [<strong>Chernoff vs Chebyshev</strong>] We have a standard six-sided die. Let <math>X</math> be the number of times a 6 occurs in <math>n</math> throws off the die. Compare the best upper bounds on <math>\textbf{Pr}[X\geq n/4]</math> that you can obtain using Chebyshev's inequality and Chernoff bounds. | ||
</li> | </li> | ||
<li> | <li> | ||
[<strong> | [<math>k</math><strong>-th moment bound]</strong> Let <math>X</math> be a random variable with expectation <math>0</math> such that moment generating function <math>\mathbf{E}[\exp(t|X|)]</math> is finite for some <math> t > 0 </math>. We can use the following two kinds of tail inequalities for <math> X </math>: | ||
</li> | </li> | ||
</ul><nowiki> </nowiki>'''''Chernoff Bound''''' | |||
:<math> | |||
\begin{align} | |||
\mathbf{Pr}[|X| \geq \delta] \leq \min_{t \geq 0} \frac{\mathbf{E}[e^{t|X|}]}{e^{t\delta}} | |||
\end{align} | |||
</math> | |||
'''''<math>k</math>th-Moment Bound''''' | |||
:<math> | |||
\begin{align} | |||
\mathbf{Pr}[|X| \geq \delta] \leq \frac{\mathbf{E}[|X|^k]}{\delta^k} | |||
\end{align} | |||
</math> | |||
</ | # Show that for each <math>\delta</math>, there exists a choice of <math>k</math> such that the <math>k</math>th-moment bound is no weaker than the Chernoff bound. (Hint: Use the probabilistic method.) | ||
# Why would we still prefer the Chernoff bound to the (seemingly) stronger <math>k</math>-th moment bound? | |||
<ul> | <ul> | ||
<li>[<strong>Chernoff bound meets graph theory</strong>] | <li>[<strong>Chernoff bound meets graph theory</strong>] | ||
<ul> | <ul> |
Latest revision as of 08:49, 7 June 2023
- 每道题目的解答都要有完整的解题过程,中英文不限。
- 我们推荐大家使用LaTeX, markdown等对作业进行排版。
- Bonus problem为附加题(选做)。
Assumption throughout Problem Set 4
Without further notice, we are working on probability space [math]\displaystyle{ (\Omega,\mathcal{F},\mathbf{Pr}) }[/math].
Without further notice, we assume that the expectation of random variables are well-defined.
The term [math]\displaystyle{ \log }[/math] used in this context refers to the natural logarithm.
Problem 1 (Continuous Random Variables, 30 points)
- [Density function] Determine the value of [math]\displaystyle{ C }[/math] such that [math]\displaystyle{ f(x) = C\exp(-x-e^{-x}), x\in \mathbb{R} }[/math] is a probability density function (PDF) for a continuous random variable.
- [Independence] Let [math]\displaystyle{ X }[/math] and [math]\displaystyle{ Y }[/math] be independent and identically distributed continuous random variables with cumulative distribution function (CDF) [math]\displaystyle{ F }[/math] and probability density function (PDF) [math]\displaystyle{ f }[/math]. Find out the density functions of [math]\displaystyle{ V = \max\{X,Y\} }[/math] and [math]\displaystyle{ U = \min\{X,Y\} }[/math].
- [Correlation] Let [math]\displaystyle{ X }[/math] be uniformly distributed on [math]\displaystyle{ (-1,1) }[/math] and [math]\displaystyle{ Y_k = \cos(k \pi X) }[/math] for [math]\displaystyle{ k=1,2,\ldots,n }[/math]. Are the random variables [math]\displaystyle{ Y_1, Y_2, \ldots, Y_n }[/math] correlated? independent? You should prove your claim rigorously.
- [Expectation of random variables (I)]
Let [math]\displaystyle{ X }[/math] be a continuous random variable with mean [math]\displaystyle{ \mu }[/math] and cumulative distribution function (CDF) [math]\displaystyle{ F }[/math].
- Suppose [math]\displaystyle{ X \ge 0 }[/math]. Show that [math]\displaystyle{ \int_{0}^a F(x) dx = \int_{a}^{\infty} [1-F(x)] dx }[/math] if and only if [math]\displaystyle{ a = \mu }[/math].
- Suppose [math]\displaystyle{ X }[/math] has finite variance. Show that [math]\displaystyle{ g(a) = \mathbb{E}((X-a)^2) }[/math] achieves the minimum when [math]\displaystyle{ a = \mu }[/math].
- [Expectation of random variables (II)] Let [math]\displaystyle{ X, Y }[/math] be two independent and identically distributed continuous random variables with cumulative distribution function (CDF) [math]\displaystyle{ F }[/math]. Furthermore, [math]\displaystyle{ X,Y \ge 0 }[/math]. Show that [math]\displaystyle{ \mathbb{E}[|X-Y|] = 2 \left(\mathbb{E}[X] - \int_{0}^{\infty} (1-F(x))^2 dx\right) }[/math]
- [Conditional distribution] Let [math]\displaystyle{ X }[/math] and [math]\displaystyle{ Y }[/math] be two random variables. The joint density of [math]\displaystyle{ X }[/math] and [math]\displaystyle{ Y }[/math] is given by [math]\displaystyle{ f(x,y) = c(x^2 - y^2)e^{-x} }[/math], where [math]\displaystyle{ 0\leq x \lt \infty }[/math] and [math]\displaystyle{ -x\leq y \leq x }[/math]. Here, [math]\displaystyle{ c\in \mathbb{R}_+ }[/math] is a constant. Find out the conditional distribution of [math]\displaystyle{ Y }[/math], given [math]\displaystyle{ X = x }[/math].
- [Uniform Distribution (I)] Let [math]\displaystyle{ P_i = (X_i,Y_i), 1\leq i\leq n }[/math], be independent, uniformly distributed points in the unit square [math]\displaystyle{ [0,1]^2 }[/math]. A point [math]\displaystyle{ P_i }[/math] is called "peripheral" if, for all [math]\displaystyle{ r = 1,2,\cdots,n }[/math], either [math]\displaystyle{ X_r \leq X_i }[/math] or [math]\displaystyle{ Y_r \leq Y_i }[/math], or both. Find out the expected number of peripheral points.
- [Uniform Distribution (II)] Derive the moment generating function of the standard uniform distribution, i.e., uniform distribution on [math]\displaystyle{ (0,1) }[/math].
- [Exponential distribution] Let [math]\displaystyle{ X }[/math] have an exponential distribution. Show that [math]\displaystyle{ \textbf{Pr}[X\gt s+x|X\gt s] = \textbf{Pr}[X\gt x] }[/math], for [math]\displaystyle{ x,s\geq 0 }[/math]. This is the memoryless property. Show that the exponential distribution is the only continuous distribution with this property.
- [Normal distribution(I)] Let [math]\displaystyle{ X,Y\sim N(0,1) }[/math] be two independent and identically distributed normal random variables. Let [math]\displaystyle{ Z = X-Y }[/math]. Find the density function of [math]\displaystyle{ Z }[/math] and [math]\displaystyle{ |Z| }[/math] respectively.
- [Normal distribution(II)] Let [math]\displaystyle{ X }[/math] have the [math]\displaystyle{ N(0,1) }[/math] distribution and let [math]\displaystyle{ a\gt 0 }[/math]. Show that the random variable [math]\displaystyle{ Y }[/math] given by [math]\displaystyle{ \begin{equation*} Y = \begin{cases} X, & |X|\lt a \\ -X, & |X|\geq a \end{cases} \end{equation*} }[/math] has the [math]\displaystyle{ N(0,1) }[/math] distribution, and find an expression for [math]\displaystyle{ \rho(a) = \textbf{Cov}(X,Y) }[/math] in terms of the density function [math]\displaystyle{ \phi }[/math] of [math]\displaystyle{ X }[/math].
- [Random process (I)]
Given a real number [math]\displaystyle{ U\lt 1 }[/math] as input of the following process, find out the expected returning value.
Process 1 - Input: real numbers [math]\displaystyle{ U \lt 1 }[/math];
- initialize [math]\displaystyle{ x = 1 }[/math] and [math]\displaystyle{ count = 0 }[/math];
- while [math]\displaystyle{ x \gt U }[/math] do
- choose [math]\displaystyle{ y \in (0,1) }[/math] uniformly at random;
- update [math]\displaystyle{ x = x * y }[/math] and [math]\displaystyle{ count = count + 1 }[/math];
- return [math]\displaystyle{ count }[/math];
- [Random process (II)]
Given a real number [math]\displaystyle{ U\lt 1 }[/math] as input of the following process, find out the expected returning value.
Process 2 - Input: real numbers [math]\displaystyle{ U \lt 1 }[/math];
- initialize [math]\displaystyle{ x = 0 }[/math] and [math]\displaystyle{ count = 0 }[/math];
- while [math]\displaystyle{ x \lt U }[/math] do
- choose [math]\displaystyle{ y \in (0,1) }[/math] uniformly at random;
- update [math]\displaystyle{ x = x + y }[/math] and [math]\displaystyle{ count = count + 1 }[/math];
- return [math]\displaystyle{ count }[/math];
- [Random semicircle] We sample [math]\displaystyle{ n }[/math] points within a circle [math]\displaystyle{ C=\{(x,y) \in \mathbb{R}^2 \mid x^2+y^2 \le 1\} }[/math] independently and uniformly at random (i.e., the density function [math]\displaystyle{ f(x,y) \propto 1_{(x,y) \in C} }[/math]). Find out the probability that they all lie within some semicircle of the original circle [math]\displaystyle{ C }[/math]. (Hint: you may apply the technique of change of variables, see function of random variables or Chapter 4.7 in [GS])
- [Stochastic domination] Let [math]\displaystyle{ X, Y }[/math] be continuous random variables. Show that [math]\displaystyle{ X }[/math] dominates [math]\displaystyle{ Y }[/math] stochastically if and only if [math]\displaystyle{ \mathbb{E}[f(X)]\geq \mathbb{E}[f(Y)] }[/math] for any non-decreasing function [math]\displaystyle{ f }[/math] for which the expectations exist.
Problem 2 (Modes of Convergence, 15 points) (Bonus problem)
-
[Connection of convergence modes (I)] Let [math]\displaystyle{ (X_n)_{n \ge 1}, (Y_n)_{n \ge 1}, X, Y }[/math] be random variables and [math]\displaystyle{ c\in\mathbb{R} }[/math] be a real number.
- Suppose [math]\displaystyle{ X_n \overset{D}{\to} X }[/math] and [math]\displaystyle{ Y_n \overset{D}{\to} c }[/math]. Prove that [math]\displaystyle{ X_nY_n \overset{D}{\to} cX }[/math].
- Construct an example such that [math]\displaystyle{ X_n \overset{D}{\to} X }[/math] and [math]\displaystyle{ Y_n \overset{D}{\to} Y }[/math] but [math]\displaystyle{ X_nY_n }[/math] does not converge to [math]\displaystyle{ XY }[/math] in distribution.
- [Connection of convergence modes (II)] Let [math]\displaystyle{ (X_n)_{n \ge 1}, X }[/math] be random variables. Prove that [math]\displaystyle{ X_n \overset{P}{\to} X }[/math] if and only if for every subsequence [math]\displaystyle{ X_{n(m)} }[/math], there exists a further subsequence [math]\displaystyle{ Y_k = X_{n(m_k)} }[/math] that converges almost surely to [math]\displaystyle{ X }[/math]. (Hint: you may use the first Borel-Cantelli lemma.)
- [Extension of Borel-Cantelli Lemma] Let [math]\displaystyle{ (A_n)_{n \ge 1} }[/math] be events. Suppose [math]\displaystyle{ \sum_{n \ge 1} \mathbf{Pr}(A_n)=+\infty }[/math]. Show that [math]\displaystyle{ \mathbf{Pr}(A_n \text{ i.o.}) \ge \limsup_{n \to \infty} \frac{ \left(\sum_{k=1}^n\mathbf{Pr}(A_k)\right)^2 }{\sum_{1\le j,k \le n} \mathbf{Pr}(A_j \cap A_k)} }[/math].
Problem 3 (LLN and CLT, 15 points + 5 points)
In this problem, you may apply the results of Laws of Large Numbers (LLN) and the Central Limit Theorem (CLT) to solve the problems.
- [St. Petersburg paradox] Consider the well-known game involving a fair coin. In this game, if it takes [math]\displaystyle{ k }[/math] tosses to obtain a head, you will win [math]\displaystyle{ 2^k }[/math] dollars as the reward. Despite the game's expected reward being infinite, people tend to offer relatively modest amounts to participate. The following provides a mathematical explanation for this phenomenon.
- For each [math]\displaystyle{ n \ge 1 }[/math], let [math]\displaystyle{ X_{n,1}, X_{n,2},\ldots, X_{n,k} }[/math] be independent random variables. Furthermore, let [math]\displaystyle{ b_n \gt 0 }[/math] be real numbers with [math]\displaystyle{ b_n \to \infty }[/math] and [math]\displaystyle{ \widetilde{X}_{n,k} = X_{n,k} \mathbf{1}_{|X_{n,k}| \le b_n} }[/math] for all [math]\displaystyle{ 1 \le k \le n }[/math]. If [math]\displaystyle{ \sum_{k=1}^n \mathbf{Pr}(|X_{n,k}| \gt b_n) \to 0 }[/math] and [math]\displaystyle{ b_n^{-2} \sum_{k=1}^n \mathbf{E}[\widetilde{X}_{n,k}^2] \to 0 }[/math] when [math]\displaystyle{ n \to \infty }[/math], then [math]\displaystyle{ (S_n-a_n)/b_n \overset{P}{\to} 0 }[/math], where [math]\displaystyle{ S_n = \sum_{k=1}^n X_{n,k} }[/math] and [math]\displaystyle{ a_n = \sum_{k=1}^n \mathbf{E}[\widetilde{X}_{n,k}] }[/math].
- Let [math]\displaystyle{ S_n }[/math] be the total winnings after playing [math]\displaystyle{ n }[/math] rounds of the game. Prove that [math]\displaystyle{ \frac{S_n}{n \log_2 n} \overset{P}{\to} 1 }[/math]. (Therefore, a fair price to play this game [math]\displaystyle{ n }[/math] times is roughly [math]\displaystyle{ n \log_2 n }[/math] dollars)
- (Bonus problem, 5 points) Let [math]\displaystyle{ S_n }[/math] be the total winnings after playing [math]\displaystyle{ n }[/math] rounds of the game. Prove that [math]\displaystyle{ \limsup_{n \to \infty} \frac{S_n}{n \log_2 n} = \infty }[/math] almost surely. (Hint: You may use Borel-Cantelli lemmas)
- [Asymptotic equipartition property] Let [math]\displaystyle{ X_1,X_2,\ldots \in \{1,2,\ldots,r\} }[/math] be independent random variables with density function [math]\displaystyle{ p }[/math]. Let [math]\displaystyle{ \pi_n(\omega) = \prod_{i=1}^n p(X_i(\omega)) }[/math] be the probability of the realization we observed in the first [math]\displaystyle{ n }[/math] random variables. Let [math]\displaystyle{ H = -\sum_{k=1}^r p(k) \log p(k) }[/math] be the entropy of [math]\displaystyle{ X_1 }[/math]. Prove that for any [math]\displaystyle{ \epsilon \gt 0 }[/math], [math]\displaystyle{ \mathbf{Pr}\left(e^{-n(H+\epsilon)} \lt \pi_n(\omega) \lt e^{-n(H-\epsilon)}\right) \to 1 }[/math] when [math]\displaystyle{ n \to \infty }[/math].
- [Normalized sum] Let [math]\displaystyle{ X_1,X_2,\ldots }[/math] be i.i.d. random variables with [math]\displaystyle{ \mathbf{E}[X_1] = 0 }[/math] and [math]\displaystyle{ \mathbf{Var}[X_1] = \sigma^2 \in (0,+\infty) }[/math]. Show [math]\displaystyle{ \frac{\sum_{k=1}^n X_k}{\left(\sum_{k=1}^n X_k^2\right)^{1/2}} \overset{D}{\to} N(0,1) }[/math] as [math]\displaystyle{ n \to \infty }[/math].
Problem 4 (Concentration of measure)
- [Tossing coins] We repeatedly toss a fair coin (with an equal probability of heads and tails). Let the random variable [math]\displaystyle{ X }[/math] be the number of throws required to obtain a total of [math]\displaystyle{ n }[/math] heads. Show that [math]\displaystyle{ \textbf{Pr}[X \gt 2n + 2\sqrt{n\log n}]\leq O(1/n) }[/math].
- [Chernoff vs Chebyshev] We have a standard six-sided die. Let [math]\displaystyle{ X }[/math] be the number of times a 6 occurs in [math]\displaystyle{ n }[/math] throws off the die. Compare the best upper bounds on [math]\displaystyle{ \textbf{Pr}[X\geq n/4] }[/math] that you can obtain using Chebyshev's inequality and Chernoff bounds.
- [[math]\displaystyle{ k }[/math]-th moment bound] Let [math]\displaystyle{ X }[/math] be a random variable with expectation [math]\displaystyle{ 0 }[/math] such that moment generating function [math]\displaystyle{ \mathbf{E}[\exp(t|X|)] }[/math] is finite for some [math]\displaystyle{ t \gt 0 }[/math]. We can use the following two kinds of tail inequalities for [math]\displaystyle{ X }[/math]:
Chernoff Bound
- [math]\displaystyle{ \begin{align} \mathbf{Pr}[|X| \geq \delta] \leq \min_{t \geq 0} \frac{\mathbf{E}[e^{t|X|}]}{e^{t\delta}} \end{align} }[/math]
[math]\displaystyle{ k }[/math]th-Moment Bound
- [math]\displaystyle{ \begin{align} \mathbf{Pr}[|X| \geq \delta] \leq \frac{\mathbf{E}[|X|^k]}{\delta^k} \end{align} }[/math]
- Show that for each [math]\displaystyle{ \delta }[/math], there exists a choice of [math]\displaystyle{ k }[/math] such that the [math]\displaystyle{ k }[/math]th-moment bound is no weaker than the Chernoff bound. (Hint: Use the probabilistic method.)
- Why would we still prefer the Chernoff bound to the (seemingly) stronger [math]\displaystyle{ k }[/math]-th moment bound?
- [Chernoff bound meets graph theory]
- Show that with a probability approaching 1 (as [math]\displaystyle{ n }[/math] tends to infinity), the Erdős–Rényi random graph [math]\displaystyle{ \textbf{G}(n,1/2) }[/math] has the property that the maximum degree is [math]\displaystyle{ (\frac{n}{2} + O(\sqrt{n\log n})) }[/math].
- Show that with a probability approaching 1 (as [math]\displaystyle{ n }[/math] tends to infinity), the Erdős–Rényi random graph [math]\displaystyle{ \textbf{G}(n,1/2) }[/math] has the property that the diameter is exactly 2. The diameter of a graph [math]\displaystyle{ G }[/math] is the maximum distance between any pair of vertices.